${K_3}\left[ {Cr{{\left( {{C_2}{O_4}} \right)}_3}} \right]$ માં $Cr$નો સવર્ગાંક અને ઓક્સિડેશન અવસ્થા અનુક્રમે છે ... .
AIPMT 1995, Medium
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b (b)Its coordination number will be $ 6$ because it is bonded with three bidentale ligands.
Oxi. No. of $Cr$ in $\mathop {{K_3}}\limits_{ - 1} [Cr\mathop {{{({C_2}{O_4})}_3}}\limits_{ - 2} ]$ is
$x + 3( - 2) + 3( + 1) = 0$ $ \Rightarrow \,\,x = + 3$
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