$P V=\frac{1}{3} m n V_{r m s}^{2}=\frac{2}{3} \times \frac{1}{2} m n v_{\text {rms }}^{2}=\frac{2}{3} k T$
Boyle's law state that at constant temperature average $K E$ is constant, So, $v_{\text {rms }}$ Memains unchanged. If volume increases pressure of gas decreases.
i.e., $P V=$ constant .
Charle's law state that if we allow the volume to change to maintain constant pressure the volume will increase with increasing temperature
$\text { i.e., } V=K T$
$\therefore$ Option $(c)$ is correct.
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[given, $hc =1240\,eV - nm , e =1.6 \times 10^{-{ }^{19}\,C }$ )

$Image$
$1.$ Light travels as a
$(A)$ parallel beam in each medium
$(B)$ convergent beam in each medium
$(C)$ divergent beam in each medium
$(D)$ divergent beam in one medium and convergent beam in the other medium.
$2.$ The phases of the light wave at $\mathrm{c}, \mathrm{d}, \mathrm{e}$ and $\mathrm{f}$ are $\phi_{\mathrm{c}}, \phi_{\mathrm{d}}, \phi_{\mathrm{e}}$ and $\phi_{\mathrm{f}}$ respectively. It is given that $\phi_{\mathrm{c}} \neq \phi_{\mathrm{f}}$
$(A)$ $\phi_{\mathrm{c}}$ cannot be equal to $\phi_{\mathrm{d}}$
$(B)$ $\phi_{\mathrm{a}}$ can be equal to $\phi_{\mathrm{e}}$
$(C)$ $\left(\phi_{\mathrm{d}}-\phi_t\right)$ is equal to $\left(\phi_{\mathrm{c}}-\phi_{\mathrm{e}}\right)$
$(D)$ $\left(\phi_{\mathrm{d}}-\phi_c\right)$ is not equal to $\left(\phi_{\mathrm{f}}-\phi_e\right)$
$3.$ Speed of the light is
$(A)$ the same in medium-$1$ and medium-$2$
$(B)$ larger in medium-$1$ than in medium-$2$
$(C)$ larger in medium-$2$ than in medium-$1$
$(D)$ different at $\mathrm{b}$ and $\mathrm{d}$
Give the answer question $1, 2$ and $3.$


