MCQ
$KMnO_4$ acts as an oxidizing agent in weak alkaline medium. When weak alkaline $KMnO_4$ is treated with $KI,$ iodide ion is oxidized to $.........$
- A$I_2$
- B$IO^-$
- ✓$IO^-_3$
- D$IOO^-_4$
$\mathrm{I}+6 \mathrm{OH}^{-} \rightarrow \mathrm{IO}_{3}^{-}+3 \mathrm{H}_{2} \mathrm{O}+6 \mathrm{e}^{-}$
When alkaline KMnO4 is treated with KI, I - is oxidised to IO $_{3}$. .
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(A)$ Sulphanilic acid $(B)$ Picric acid $(C)$ Aspirin $(D)$ Ascorbic acid
$(A)$ ${SO}_{3}$ $(B)$ ${NO}_{3}^{-}$ $(C)$ ${PCl}_{3}$ $(D)$ ${CO}_{3}^{2-}$