Let \(x\) be oxidation state of oxygen. The oxidation state of \(K\) is \(+1.\) Hence
\(+1+2(x)=0\)
\(2x=-1\)
\(x=-\frac {1}{2}\)
$xC{l_2}\, + 6O{H^ - }\, \to \,Cl{O_3}^ - \, + \,yC{l^ - } + 3{H_2}O$
આપેલ : $2 Cu ^{2+}+4 I ^{-} \rightarrow Cu _{2} I _{2}+ I _{2}$
$I _{2}+2 S _{2} O _{3}{ }^{2-} \rightarrow 2 I ^{-}+ S _{4} O _{6}{ }^{2-}$
$14{H^ + } + C{r_2}O_7^{2 - } + 3Ni \to 2C{r^{3 + }} + 7{H_2}O + 3N{i^{2 + }}$