$\therefore \rho = \frac{{R \times a}}{l} = \frac{{50 \times 1}}{{0.5}} = 100$
$\therefore {\Lambda _{eq}} = \frac{{1000 \times K}}{N} = \frac{{1000 \times 1}}{{N \times \rho }} = \frac{{1000 \times 1}}{{1 \times 100}} = 10$
$\Delta G_{f}^{o}\left(A g_{2} O\right)=-11.21\, kJ\,mol ^{-1}$
$\Delta G_{f}^{o}(Z n O)=-318.3\, kJ \,mol ^{-1}$
ત્યારે $E^{o}$કોષ નો બટન શેલ.........$V$ શું હશે ?
$\lambda_{\mathrm{m}\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{x} \;\mathrm{S}\; \mathrm{cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}\left(\mathrm{K}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{y} \;\mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}(\mathrm{CH_3} \mathrm{COOK})}^{0}=\mathrm{z}\; \mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\mathrm{CH}_{3} \mathrm{COOH}$ માટે $\lambda_{\mathrm{m}}^{0}\left(\mathrm{in}\; \mathrm{S} \;\mathrm{cm}^{2} \mathrm{mol}^{-1}\right)$ શું હશે ?
$2 \mathrm{H}_{(\mathrm{aq})}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2(\mathrm{~g})$
${\left[\mathrm{H}^{+}\right]=1 \mathrm{M}, \mathrm{P}_{\mathrm{H}_2}=2 \mathrm{~atm}}$
(Given: $2.303 \mathrm{RT} / \mathrm{F}=0.06 \mathrm{~V}, \log 2=0.3$ )
$ = 1.33\,V$ ; $E_{Cl/C{l^ - }}^ o = 1.36\,V$
ઉપરની માહિતીના આધારે પ્રબળ ઓક્સિડેશન કર્તા કયો છે?