MCQ
Laboratory method for the preparation of acetyl chloride is
- ✓$C{H_3}COOH + SOC{l_2} \to C{H_3}COCl$
- B$C{H_3}COOH + PC{l_3} \to C{H_3}COCl$
- C$C{H_3}COONa + PC{l_3} \to C{H_3}COCl$
- DAll of these
$CH _3 COOH + SOC _2 \longrightarrow CH _3 COC 1+ HCl + SO _2 \uparrow$
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$Cl_2(aq)+H_2SO_4(aq) \rightarrow S(s)+2H^+(aq)+2Cl^-$
The rate equation for this reaction is
rate $=k[Cl_2][H_2S]$
Which of these mechanisms is/are consistent with this rate equation ?
$A.\,\, Cl_2 + H_2S \rightarrow H^+ + Cl^- + Cl^+ + HS^-\,\, (slow)$
$Cl^+ +HS^- \rightarrow H^+ +Cl^- +S \,(fast)$
$B.\,\, H_2S \rightleftharpoons H^+ + HS^-\,$ (fast equilibrium)
$Cl_2^+ + HS^- \rightarrow 2CI^- + H^+ + S\,\, (Slow)$
|
सूची-$I$ coordination compounds |
सूची-$II$ numbar of unpaired electrons |
| $A$ $\left[ Cr ( CN )_6\right]^{3-}$ | $I$ $0$ |
| $B$ $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$ | $II$ $3$ |
| $C$ $\left[ Co \left( NH _3\right)_6\right]^{3+}$ | $III$ $2$ |
| $D$ $\left[ Ni \left( NH _3\right)_6\right]^{2+}$ | $IV$ $4$ |
Choose the correct answer from the options given below :-
| Column$-I$ | Column$-II$ |
| $(a)$ $\mathrm{XeF}_{4}$ | $(i)$ pyramidal |
| $(b)$ $\mathrm{XeF}_{6} $ | $(ii)$ square planar |
| $(c)$ $\mathrm{XeOF}_{4}$ | $(iii)$ distorted octahedral |
| $(d)$ $\mathrm{XeO}_{3} $ | $(iv)$ square pyramidal |
code : $(a) \quad (b)\quad (c) \quad (d)$