_ ClC H_2 COONa = 224 ;oh m^ - 1 ,c m^2 ,gme q^ - 1 , _ NaCl = 38… - Vidyadip

MCQ

${\lambda _{ClC{H_2}COONa}} = 224\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,

${\lambda _{NaCl}} = 38.2\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,

${\lambda _{HCl}} = 203\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,

What is the value of ${\lambda _{ClC{H_2}COOH}}$ .............. ${\rm{Oh}}{{\rm{m}}^{ - 1}}{\mkern 1mu} {\rm{c}}{{\rm{m}}^2}{\rm{gm}}\,{\rm{e}}{{\rm{q}}^{ - 1}}$

A
$288.5$
B
$289.5$
✓
$388.5$
D
$59.5$

✓

Answer

Correct option: C.

$388.5$

c
(c)$ClC{H_2}COONa + HCl \to ClC{H_2}COOH + NaCl$

${\lambda _{ClC{H_2}COONa}}\, + \,{\lambda _{HCl}}\,= \,{\lambda _{ClC{H_2}COOH}}\, + \,{\lambda _{NaCl}}$

$224 + 203 = {\lambda _{ClC{H_2}COOH}} + 38.2$

${\lambda _{ClC{H_2}COOH}} = 427 - 38.2 = 388.8\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$.

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