MCQ
Last three digits of the number $N = 7^{100} - 3^{100}$ are
- A$100$
- B$300$
- C$500$
- ✓$0$
$= 2 [^{100}C_1 5^{99} · 2 + ^{100}C_3 5^{97} · 2^3 + ....... + ^{100}C_{99}5 · 2^{99}]$
$= 2 [1000 · 5^{98} + ^{100}C_3 5^{94} + ....... + 1000 · 2^{98}]$
$\Rightarrow$ minimum $000$ as last three digits.
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