MCQ
Least integer in the range of $f(x)$=$\sqrt {(x + 4)(1 - x)}  - {\log _2}x$ is
  • A
    $-2$
  • B
    $-1$
  • $0$
  • D
    $1$

Answer

Correct option: C.
$0$
c
$f(x)=\sqrt{(x+4)(1-x)}+\log _{1 / 2} x$

$\because$ $'f'$ is decreasing

minimum value is $f(1)=0.$

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