MCQ
Least value of $E = \frac{{25{{\sec }^4}x - 50{{\sec }^2}x + 74}}{{{{\tan }^2}x}}$ is
- A$50$
- ✓$70$
- C$75$
- D$90$
$=\frac{25\left(\sec ^{2} x-1\right)^{2}}{\tan ^{2} x}+\frac{49}{\tan ^{2} x}$
$\Rightarrow 25 \tan ^{2} x+49 \cot ^{2} x$
$\therefore \quad E_{\min }=2 \times 5 \times 7=70$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.