$x+4(0)=0 $
$x=0$
The electronic configuration of $Ni$ is $[ Ar ] 3 d ^{8} 4 s ^{2} 4 p ^{0} .$ The orbital diagram of nickel in the presence of strong filed ligand $CO$ is shown below.
As no unpaired electron is present in this complex, so it is diamagnetic.
$CoCl _{3} . xNH _{3}+ AgNO _{3}( aq ) \rightarrow$
જો $AgCl$ ના બે સમતુલ્યો અવક્ષેપિત થાય તો $x$ નું મૂલ્ય $\dots\dots$ થશે.
$[Co(en)_3]\,[Cr(C_2O_4)_3]$
$[Cu(NH_3)_4]\, [CuCl_4]$
$[Ni(en)_3]\,[Co(NO_2)_6]$