Question
$\left(1-x+2 x^3\right)^{10}$ में $\mathrm{x}^7$ का गुणांक है_________
where $r_1+r_2+r_3=10$ and $r_2+3 r_3=7$
$\begin{array}{lll}r_1 & r_2 & r_3 \\ 3 & 7 & 0 \\ 5 & 4 & 1 \\ 7 & 1 & 2\end{array}$
Required coefficient
$=\frac{10 !}{3 ! .7 !}(-1)^7+\frac{10 !}{5 ! .4 !}(-1)^4(2)+\frac{10 !}{7 ! \cdot 2 !}(-1)^1(2)^2$
$=-120+2520-1440=960$
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