MCQ
$\left(1+\tan ^2 A\right)(1+\sin A )(1-\sin A )$ is equal to
  • A
    $\frac{\cos ^2 A}{\sec ^2 A}$
  • $1$
  • C
    $0$
  • D
    $2$

Answer

Correct option: B.
$1$
$\text { (b) }\left(1+\tan ^2 A\right)(1+\sin A )(1-\sin A )$
$\quad=\left(1+\tan ^2 A\right)\left\{(1)^2-\sin ^2 A\right\}$
$\left\{\therefore( a + b )( a - b )=\left( a ^2- b ^2\right)\right\}$

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