MCQ
If triangle $\text{ABC}$ is similar to triangle $\text{DEF},$ then,
- A$\frac{\text{AB}}{\text{FD}}=\frac{\text{BC}}{\text{EF}}=\frac{\text{CA}}{\text{DE}}$
- B$\frac{\text{AB}}{\text{DE}}=\frac{\text{BC}}{\text{DF}}=\frac{\text{CA}}{\text{EF}}$
- ✓$\frac{\text{AB}}{\text{DE}}=\frac{\text{BC}}{\text{EF}}=\frac{\text{CA}}{\text{FD}}$
- D$\frac{\text{AB}}{\text{BC}}=\frac{\text{CA}}{\text{DE}}=\frac{\text{EF}}{\text{FD}}$