MCQ
$\left(3^2-2^2\right) \times\left(\frac{2}{3}\right)^{-3}=?$
  • A
    $\frac{45}{8}$
  • B
    $\frac{8}{45}$
  • C
    $\frac{8}{135}$
  • $\frac{135}{8}$

Answer

Correct option: D.
$\frac{135}{8}$
D

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