| , * 20 c 11 & 12 & 13 12 & 13 & 14 13 & 14 & 15 , | = - Vidyadip

MCQ

$\left| {\,\begin{array}{*{20}{c}}{11}&{12}&{13}\\{12}&{13}&{14}\\{13}&{14}&{15}\end{array}\,} \right| = $

A
$1$
✓
$0$
C
$-1$
D
$67$

✓

Answer

Correct option: B.

$0$

b
(b)Apply ${C_3} \to {C_3} - {C_2}$ and ${C_2} \to {C_2} - {C_1}$.

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