$\left| {\,\begin{array}{*{20}{c}}1&1&1\\{bc}&{ca}&{ab}\\{b + c}&{c + a}&{a + b}\end{array}\,} \right|$ =
  • A$1$
  • B$0$
  • C$(a - b)(b - c)(c - a)$
  • D$(a + b)(b + c)(c + a)$
Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    $A$ અને $B$ એ $3 \times 3$ કક્ષાનો શ્રેણિક છે કે જેથી $AB + A + B = 0$ હોય તો $. . . .$
    View Solution
  • 2
    જો $\omega $ એ એકનું કાલ્પનિક ઘનમૂળ હોય તો $\Delta = \left| {\begin{array}{*{20}{c}}1&{2\omega }\\\omega &{{\omega ^2}}\end{array}} \right|$, તો ${\Delta ^2} = . . .$
    View Solution
  • 3
    $\left[ {\begin{array}{*{20}{c}}7&1&2\\9&2&1\end{array}} \right]\,\left[ \begin{array}{l}3\\4\\5\end{array} \right] + 2\left[ \begin{array}{l}4\\2\end{array} \right] =\  . . .... .$
    View Solution
  • 4
    જો $A = \left[ {\begin{array}{*{20}{c}}1&3\\2&1\end{array}} \right],$ તો $|{A^2} - 2A|=\ .... . . . $
    View Solution
  • 5
    જો $..........$ તો $\mathrm{A}$ અને $\mathrm{B}$ એકબીજાના વ્યસ્ત શ્રેણિક છે.
    View Solution
  • 6
    શ્રેણિક $\left[ {\begin{array}{*{20}{c}}1&0&0\\0&1&0\\0&0&1\end{array}} \right]$ નો વ્યસ્ત મેળવો.
    View Solution
  • 7
    જો  $A$ એ  $3 \times 3$ નો વાસ્તવિક ક્ષેણિક છે.  $\mathrm{A}\left(\begin{array}{l}1 \\ 0 \\ 1\end{array}\right)=2\left(\begin{array}{l}1 \\ 0 \\ 1\end{array}\right), \mathrm{A}\left(\begin{array}{l}-1 \\ 0 \\ 1\end{array}\right)=4\left(\begin{array}{l}-1 \\ 0 \\ 1\end{array}\right), \mathrm{A}\left(\begin{array}{l}0 \\ 1 \\ 0\end{array}\right)=2\left(\begin{array}{l}0 \\ 1 \\ 0\end{array}\right)$. તો  $(A-3 I)\left(\begin{array}{l}x \\ y \\ z\end{array}\right)=\left(\begin{array}{l}1 \\ 2 \\ 3\end{array}\right)$ એ 
    View Solution
  • 8
    સમીકરણની સંહતિ $3x - 2y + z = 0$, $\lambda x - 14y + 15z = 0$, $x + 2y - 3z = 0$ ને $x = y = z = 0$ સિવાયનો ઉકેલ હોય તો $\lambda $ મેળવો.
    View Solution
  • 9
    જો સમીકરણ સંહતિ $2 x+y+z=5$  ;   $x-y+z=3$  ;  $x+y+a z=b$  નો ઉકેલગણ ખાલીગણ હોય તો  . . . 
    View Solution
  • 10
    $\left| {\,\begin{array}{*{20}{c}}{a + b}&{b + c}&{c + a}\\{b + c}&{c + a}&{a + b}\\{c + a}&{a + b}&{b + c}\end{array}\,} \right| = K\,\,\left| {\,\begin{array}{*{20}{c}}a&b&c\\b&c&a\\c&a&b\end{array}\,} \right|\,,$ તો $K = $
    View Solution