MCQ
$\left| {\,\begin{array}{*{20}{c}}5&3&{ - 1}\\{ - 7}&x&{ - 3}\\9&6&{ - 2}\end{array}\,} \right| = 0$, then $ x$ is equal to
- A$3$
- B$5$
- C$7$
- ✓$9$
$\therefore $ $ - 10x + 90 - 42 - 81 + 42 + 9x = 0\,\,{\rm{or}}\,{\rm{ }}x = 9$.
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