Question
Let +6 (addition modulo 6) be a binary operation on S = {0, 1, 2, 3, 4, 5}. Write the value of 2 + 64−1 63−1.

Answer

The composition table for +6 on the set S = {0, 1, 2, 3, 4, 5} is
+6 0 1 2 3 4 5
0 0 1 2 3 4 5
1 1 2 3 4 5 0
2 2 3 4 5 0 1
3 3 4 5 0 1 2
4 4 5 0 1 2 3
5 5 0 1 2 3 4
'0' is the identity element for +6 from the table it is clear that
4-1 = 2 and 3-1 = 3
Now, 2 + 64-163-1 = 2 + 62 + 63
= 4 + 63
= 1

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