MCQ
Let $9 < x_1 < x_2 < \ldots < x_7$ be in an $A.P.$ with common difference $d$. If the standard deviation of $x_1, x_2 \ldots$, $x _7$ is $4$ and the mean is $\overline{ x }$, then $\overline{ x }+ x _6$ is equal to:
- A$18\left(1+\frac{1}{\sqrt{3}}\right)$
- ✓$34$
- C$2\left(9+\frac{8}{\sqrt{7}}\right)$
- D$25$