MCQ
Let $A B C$ be a triangle with $\angle C=90^{\circ}$. Draw $C D$ perpendicular to $A B$. Choose points $M$ and $N$ on sides $A C$ and $B C$ respectively such that $D M$ is parallel to $B C$ and $D N$ is parallel to $A C$. If $D M=5, D N=4$, then $A C$ and $B C$ are respectively equal to
- ✓$\frac{41}{4}, \frac{41}{5}$
- B$\frac{39}{4}, \frac{39}{5}$
- C$\frac{38}{4}, \frac{38}{5}$
- D$\frac{37}{4}, \frac{37}{5}$
