Question
Let a source of alternating e.m.f. $\text{E} = \text{E}_\circ\sin\omega\text{t}$ be connected to a capacitor of capacitance C. If 'I' is the instantaneous value of current in the circuit at instant t, then $\text{I}=\frac{\text{E}_0}{\frac{1}{\omega\text{C}}}\sin\Big(\omega\text{t}+\frac{\pi}{2}\Big).$ The capacitive reactance limits the amplitude of current in a purely capacitive circuit and it is given by $\text{X}_\text{C}=\frac{1}{\omega\text{C}}.$
- What is the unit of capacitive reactance?
- Farad
- Ampere
- Ohm
- $Ohm^{-1}$
- The capacitive reactance of a $5\mu\text{F}$ capacitor for a frequency of $10^6Hz$ is:
- $0.032\Omega$
- $2.52\Omega$
- $1.25\Omega$
- $4.51\Omega$
- In a capacitive circuit, resistance to the flow of current is offered by:
- Resistor
- Capacitor
- Inducto
- Frequency
- In a capacitive circuit, by what value of phase angle does alternating current leads the e.m.f?
- $45^\circ$
- $90^\circ$
- $75^\circ$
- $60^\circ$
- One microfarad capacitor is joined to a 200V, 50Hz alternator. The rrns current through capacitor is:
- $6.28 \times 10^{-2}A$
- $7.5 \times 10^{-4}A$
- $10.52 \times 10^{-2}A$
- $15.25 \times 10^{-2}A$


