MCQ
Let ${a_1},{a_2}...,{a_{10}}$ be a $G.P.$ If $\frac{{{a_3}}}{{{a_1}}} = 25,$ then $\frac {{{a_9}}}{{{a_{ 5}}}}$ equal
- ✓$5^4$
- B$4(5^2)$
- C$5^3$
- D$2(5^2)$
$ \Rightarrow {r^2} = 25$
Now $\frac{{{a_9}}}{{{a_5}}} = \frac{{{a_1}{r^8}}}{{{a_1}{r^4}}} = {r^4} = {\left( {25} \right)^2} = {5^4}$
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