- A$16$
- B$32$
- ✓$-16$
- D$0$
$|B|=4$
$1(8-3 \alpha)-3(4-3 \alpha)+\alpha(\alpha-2 \alpha)=4$
$-\alpha^2+6 \alpha-8=0$
$\alpha=2,4$
Given,$\alpha > 2$
So,$\alpha=2$ is rejected
$\left[\begin{array}{lll}4 & -8 & 4\end{array}\right]\left[\begin{array}{lll}1 & 3 & 4 \\ 1 & 2 & 3 \\ 4 & 4 & 4\end{array}\right]\left[\begin{array}{c}4 \\ -8 \\ 4\end{array}\right]=[-16]_{1 \times 1}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
For a binomial variate X, if $\text{n}=3$ and $\text{P(X}=1)=8\text{ P(X = 3}),$ then p =
$f(x)=\left\{\begin{array}{l}\max \left\{t^{3}-3 t\right\} ; x \leq 2 \\ t \leq x \\ x^{2}+2 x-6 ; 2 < x < 3 \\ {[x-3]+9 ; 3 \leq x \leq 5} \\ 2 x+1 \quad ; \quad x > 5\end{array}\right\}$
Where $[t]$ is the greatest integer less than or equal to $t$. Let $m$ be the number of points where $f$ is not differentiable and $I =\int\limits_{-2}^{2} f( x ) dx$. Then the ordered pair $( m , I )$ is equal to