MCQ
Let $f : (4, 6) \to (6,8)$ be a function defined by $f(x) = x + [\frac{x}{2}]$ (where $[.]$ denotes the greatest integer function) , then $f^{-1} (x)$ is euqal to
- A$x- [\frac{x}{2}]$
- B$-x -2$
- ✓$x -2$
- D$\frac{1}{x+[\frac{x}{2}]}$
$\frac{x}{2} \in(2,3)$
$\left[\frac{x}{2}\right] \in 2$
$\therefore y=x+\left[\frac{x}{2}\right]=x+2$
$y-2=x$
Or
$f^{-1}(x)=x-2$
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