MCQ
Let $f$ be a differential function such that $f'\left( x \right) = 7 - \frac{3}{4}\frac{{f\left( x \right)}}{x},\left( {x > 0} \right)$ and $f(1) \ne 4$. Then $\mathop {\lim }\limits_{x \to {0^ + }} xf\left( {\frac{1}{x}} \right)$
  • A
    exists and equals $\frac{4}{7}$
  • B
    exists and equals $4$
  • C
    does not exist.
  • D
    exists and equals $0$

Answer

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