MCQ
Let $f$ be a differential function such that $f'\left( x \right) = 7 - \frac{3}{4}\frac{{f\left( x \right)}}{x},\left( {x > 0} \right)$ and $f(1) \ne 4$. Then $\mathop {\lim }\limits_{x \to {0^ + }} xf\left( {\frac{1}{x}} \right)$
- Aexists and equals $\frac{4}{7}$
- Bexists and equals $4$
- Cdoes not exist.
- Dexists and equals $0$