MCQ
Let $f:\left[-\frac{1}{2}, 2\right] \rightarrow \mathbb{R}$ and $g:\left[-\frac{1}{2}, 2\right] \rightarrow \mathbb{R}$ be functions defined by $f(x)=\left[x^2-3\right]$ and $g(x)=|x| f(x)+|4 x-7| f(x)$, where $[y]$ denotes the greatest integer less than or equal to $y$ for $y \in \mathbb{R}$. Then

($A$) $f$ is discontinuous exactly at three points in $\left[-\frac{1}{2}, 2\right]$

($B$) $f$ is discontinuous exactly at four points in $\left[-\frac{1}{2}, 2\right]$

($C$) $g$ is $NOT$ differentiable exactly at four points in $\left(-\frac{1}{2}, 2\right)$

($D$) $g$ is $NOT$ differentiable exactly at five points in $\left(-\frac{1}{2}, 2\right)$

  • A
    $B,A$
  • B
    $B,D$
  • $B,C$
  • D
    $B,C,A$

Answer

Correct option: C.
$B,C$
c
The correct options are

$B$ f is discontinuous exactly at four points in $\left[-\frac{1}{2}, 2\right]$

$C$ g is not differentiable exactly at four points in $\left(-\frac{1}{2}, 2\right)$

f and $g:\left[-\frac{1}{2}, 2\right] \rightarrow R$

$f(x)=\left[x^2-3\right]$ and $g(x)=|x| f(x)+|4 x-7| f(x)$

$\left[x^2-3\right]$ is discontinuous at all integral points in

$\left[-\frac{1}{2^{\prime}} 2\right]$ which happens at $x=1, x=\sqrt{2}, x=\sqrt{3}, x=2$

$F$ is discontinuous at 4 points.

$g(x)=(|x|+|4 x-7|) f(x)$

$F$ is not differentiable at $x=1, \sqrt{2}, \sqrt{3}$

And $|x|+|4 x-7|$ is not differentiable at $x=0$

$x=\frac{7}{4}$

$f(x)=0 \text { in }[\sqrt{3}, 2]$

So at $\frac{7}{4}[\sqrt{3}, 2]$ the $f(x)$ is differentiable

Hence $g(x)$ is not differentiable at 4 points

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