MCQ
If $\vec{a}$ is a nonzero vector of magnitude 'a' and $\lambda$ a nonzero scalar, then $\lambda\ \vec{a}$ is unit vector if
  • A
    $\lambda=1$
  • B
    $\lambda=-1$
  • C
    $a=\big|\lambda\big|$
  • $a=1/\big|\lambda\big|$

Answer

Correct option: D.
$a=1/\big|\lambda\big|$
Given: $ \vec{a}$ is a non-zero vector of magnitude a $ \Rightarrow\ \ \ |\vec{a}|=1$
Also given $\lambda\neq0\ \text{and}\ \lambda\vec{a}$ is a unit vector.
$\Rightarrow\ \ |\lambda\vec{a}|=1\ \Rightarrow\ \ |\lambda|\big|\vec{a}\big|=1$
$\Rightarrow\ \ \ \ \ \ |\lambda|a=1\ \ \Rightarrow\ \ a=\frac{1}{|\lambda|}$
Therefore, option (D) is correct.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The horizontal force and the force inclined at an angle ${60^o}$ with the vertical, whose resultant is in vertical direction of  $ P $ $kg$, are
Choose the correct answer from the given four options:
Let the f: R → R be defined by $\text{f(x)}=2\text{x}+\cos\text{x}$ then f:
Let $f(x)=7 \tan ^8 x+7 \tan ^6 x-3 \tan ^4 x-3 \tan ^2 x$ for all $x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$. Then the correct expression$(s)$ is(are)

$(A)$ $\int^{\pi / 4} x f(x) d x=\frac{1}{12}$

$(B)$ $\int_0^{\pi / 4} f(x) d x=0$

$(C)$ $\int_0^{\pi / 4} x f(x) d x=\frac{1}{6}$

$(D)$ $\int_0^{\pi / 4} f(x) d x=1$

If $\int \sqrt{\sec 2 x-1} d x=\alpha \log _e\left|\cos 2 x+\beta+\sqrt{\cos 2 x\left(1+\cos \frac{1}{\beta} x\right)}\right|+$ constant, then $\beta-\alpha$ is equal to
The value of $\sin ^{ -1 }{ \left( \cos { \frac { 53\pi }{ 5 } } \right) }=\sin ^{ -1 }{ \left( \cos { \frac { 50\pi+3\pi }{ 5 } } \right) }:$
The value of $\int\limits_{ - 1}^1 {\frac{{dx}}{{\sqrt {\,|\,x\,|} }}} \,\,$ is
The general solution of differential equation is $(y+c)^2=c x$ where ccis an arbitrary constant. The order and degree of the differential equation are respectively:
In linear programming, objective function and objective constraints are:
If the function $y = e^{4x} + 2e^{-x}$ is a solution of the differential equation $\frac{{\frac{{{d^3}y}}{{d{x^3}}} - 13\frac{{dy}}{{dx}}}}{y} = K$ then the value of $K$ is
$Q^{+}$ denote the set of all positive rational numbers. If the binary operation $\text{a }\odot$ on $Q^{+}$ is defined as: $\text{a }\odot=\frac{\text{ab}}{2}$, then the inverse of $3$ is: