MCQ
Let $f(x) = \,\left\{ {\begin{array}{*{20}{c}} {\frac{{\sin \pi x}}{{5x}},}&{x \ne 0} \\ {k,}&{x = 0} \end{array}} \right.$ if $f(x)$ is continuous at $x = 0,$ then $k=$
- ✓$\frac{\pi }{5}$
- B$\frac{5}{\pi }$
- C$1$
- D$0$
therefore $\mathop {{\rm{lim}}}\limits_{x \to 0} f(x) = f(0)$
==> $\mathop {{\rm{lim}}}\limits_{x \to 0} \frac{{\sin \pi \,x}}{{5x}} = k$
==> $\mathop {{\rm{lim}}}\limits_{x \to 0} \left( {\frac{{\sin \pi \,x}}{{\pi x}}} \right)\,.\,\frac{\pi }{5} = k$
==> $(1)\,.\,\frac{\pi }{5} = k$ ==> $k = \frac{\pi }{5}$.
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