MCQ
Let $f(x) = x^3 -6x^2 +15x + 3.$ Then:
- A$f(x) > 0$ for all $\text{x}\in\text{R}.$
- B$f(x) > 0$ for all $\text{x}\in\text{R}.$
- ✓$f(x)$ is invertible.
- DNone of these.
$f(x) = x^3 - 6x^2 +15x + 3$
$f'(x) = 3x^2 - 12x + 15$
$= 3(x^2 - 4x + 5)$
$= 3(x^2 - 4x + 4 + 1)$
$=3(\text{x}-2)^2+\frac{1}{3}>0$
Therefore, $f(x)$ is strictly increasing function.
$\Rightarrow f^{-1}(x)$ exists.
Hence, $f(x)$ is an invertible function.
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