MCQ
Let $g(x) = 1 + x - [x]$ and $f(x) = \left\{ \begin{array}{l} - 1,\;x < 0\\0,\;\;x = 0,\;\\{\rm{1,}}\;\;\;{\rm{x}} > {\rm{0}}\end{array} \right.$then for all $x,\;f(g(x))$ is equal to
- A$x$
- ✓$1$
- C$f(x)$
- D$g(x)$
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