Let n(A) = 28,n(A ∩ B) =8, n(A∪B) =52, then n(A ∩ B′): - Vidyadip

MCQ

Let n(A) = 28,n(A ∩ B) =8, n(A∪B) =52, then n(A ∩ B′):

A
30
B
32
C
20
D
none of these

✓

Answer

20

Solution:

Given n(A) = 28, n(A ∩ B) = 8.

We have A ∩ B′ = A - A ∩ B.

This give n(A ∩ B′) = n(A) -n(A ∩ B)

or, n(A ∩ B′) = 28 - 8 = 20.

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