MCQ
Let $R$ be a rectangle, $C$ be a circle, and $T$ be a triangle in the plane. The maximum possible number of points common to the perimeters of $R, C$ and $T$ is
- A$3$
- B$4$
- C$5$
- ✓$6$

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$(A)$ $T_{20}=1604$
$(B)$ $\sum_{ k =1}^{20} T_{ k }=10510$
$(C)$ $T_{30}=3454$
$(D)$ $\sum_{ k =1}^{30} T_{ k }=35610$