MCQ
Let $S_n$ denote the sum of the first $n$ terms of an $A.P$.. If $S_4 = 16$ and $S_6 = -48$, then $S_{10}$ is equal to
- A$-410$
- B$-260$
- ✓$-320$
- D$-380$
$3\left\{ {2a + 5d} \right\} = - 48$
$2a + 3d = 8$
$2a + 5d = - 16$
$d = - 12$
${S_{10}} = 5\left\{ {44 - 9 \times 12} \right\}$
$ = - 320$
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