MCQ
Let $S_n$ denote the sum of the first $n$ terms of an $A.P$.. If $S_4 = 16$ and $S_6 = -48$, then $S_{10}$ is equal to
  • A
    $-410$
  • B
    $-260$
  • $-320$
  • D
    $-380$

Answer

Correct option: C.
$-320$
c
$2\left\{ {2a + 3d} \right\} = 16$

$3\left\{ {2a + 5d} \right\} =  - 48$

$2a + 3d = 8$

$2a + 5d =  - 16$

$d =  - 12$

${S_{10}} = 5\left\{ {44 - 9 \times 12} \right\}$

$ =  - 320$

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