MCQ
Let $[t]$ denote the greatest integer function. If $\int \limits_0^{2.4}\left[x^2\right] d x=\alpha+\beta \sqrt{2}+\gamma \sqrt{3}+\delta \sqrt{5}$, then $\alpha+\beta+\gamma+$ $\delta$ is equal to $..............$.
- ✓$6$
- B$5$
- C$4$
- D$3$
$\sqrt{2}-1+2(\sqrt{3}-\sqrt{2})+3(2-\sqrt{3})+4(\sqrt{5}-2)+5((2 \cdot 4)-\sqrt{5})$
$=9-\sqrt{2}-\sqrt{3}-\sqrt{5}$
$\alpha+\beta+\gamma+\delta=9-1-1-1=6$
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