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MATRICES — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsMATRICES3 Marks
Question
Let $\text{A}=\begin{bmatrix}2&-3\\-7&5\end{bmatrix}$ and $\text{B}=\begin{bmatrix}1&0\\2&-4\end{bmatrix},$ verify that
$(\text{A}+\text{B})^\text{T}=\text{A}^\text{T}+\text{B}^\text{T}$
✓

Answer

Given: $\text{A}=\begin{bmatrix}2&-3\\-7&5\end{bmatrix}$
$\text{A}^\text{T}=\begin{bmatrix}2&-7\\-3&5\end{bmatrix}$
$\text{B}=\begin{bmatrix}1&0\\2&-4\end{bmatrix}$
$\text{B}^\text{T}=\begin{bmatrix}1&2\\0&-4\end{bmatrix}$
Given,
$(\text{A}+\text{B})^\text{T}=\text{A}^\text{T}+\text{B}^\text{T}$
$\begin{pmatrix} \begin{bmatrix} 2&-3\\-7&5\end{bmatrix}+\begin{bmatrix} 1&0\\2&-4\end{bmatrix}\end{pmatrix}^\text{T}$ $=\begin{bmatrix}2&-3\\-7&5\end{bmatrix}^\text{T}+\begin{bmatrix}1&0\\2&-4\end{bmatrix}^\text{T}$
$\Rightarrow\begin{bmatrix}2+1&-3+0\\-7+2&5-4\end{bmatrix}^\text{T}$ $=\begin{bmatrix}2&-7\\-3&5\end{bmatrix}+\begin{bmatrix}1&2\\0&-4\end{bmatrix}$
$\Rightarrow\begin{bmatrix}3&-3\\-5&1\end{bmatrix}^\text{T}=\begin{bmatrix}2+1&-7+2\\-3+0&5-4\end{bmatrix}$
$\Rightarrow\begin{bmatrix}3&-5\\-3&1\end{bmatrix}=\begin{bmatrix}3&-5\\-3&1\end{bmatrix}$
$\Rightarrow\text{LHS}=\text{RHS}$
So,
$(\text{A}+\text{B})^\text{T}=\text{A}^\text{T}+\text{B}^\text{T}$

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