MCQ
Let the solubility of an aqueous solution of $Mg{(OH)_2}$ be $x$ then its ${k_{sp}}$ is
- ✓$4{x^3}$
- B$108{x^5}$
- C$27{x^4}$
- D$9x$
${K_{sp}} = 4{X^3}$
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$\left( i \right)\,2F{e_2}{O_3}\left( s \right) \to 4Fe\left( s \right) + 3{O_2}\left( g \right)$
${\Delta _r}{G^o} = + 1487.0\,kJ\,mo{l^{ - 1}}$
$\left( {ii} \right)\,2CO\left( g \right) + {O_2}(g) \to 2C{O_2}\left( g \right)$
${\Delta _r}{G^o} = - 514.4\,kJ\,mo{l^{ - 1}}$
Free energy change, $\Delta_rG^o$ for the reaction
$\,2F{e_2}{O_3}\left( s \right) + 6CO\left( g \right) \to 4Fe\left( s \right) + 6C{O_2}\left( g \right)$ will be .....$kJ\, mol^{-1}$
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH = C{H_2}\,\,\,\,\,} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}}
\end{array}\xrightarrow[{(ii)\,NaB{H_4}}]{{(i)\,Hg{{(OAc)}_2};{H_2}O}}$
| $Cl_2(g) \rightarrow 2Cl(g),$ | $242.3\,kJ\,mol^{-1}$ |
| $I_2(g) \rightarrow 2I(g),$ | $151.0\,kJ\,mol^{-1}$ |
| $ICl(g) \rightarrow I(g)+Cl(g),$ | $211.3\,kJ\,mol^{-1}$ |
| $I_2(s) \rightarrow I_2(g),$ | $62.76\,kJ\,mol^{-1}$ |
Given that the standard states for iodine and chlorine are $I_2(s)$ and $Cl_2(g),$ the standard enthalpy of formation for $ICl(g)$ is : ............... $\mathrm{kJ\,mol}^{-1}$
$(1)$ $Y$ is diamagnetic in nature while $Z$ is paramagnetic
$(2)$ Both $Y$ and $Z$ are coloured and have tetrahedral shape
$(3)$ In both $Y$ and $Z , \pi$-bonding occurs between $p$-orbitals of oxygen and $d$-orbitals of manganese.
$(4)$ In aqueous acidic solution, $Y$ undergoes disproportionation reaction to give $Z$ and $MnO _2$.