MCQ
The enthalpy changes for the following processes are listedbelow :

$Cl_2(g) \rightarrow 2Cl(g),$ $242.3\,kJ\,mol^{-1}$
$I_2(g) \rightarrow 2I(g),$ $151.0\,kJ\,mol^{-1}$
$ICl(g) \rightarrow I(g)+Cl(g),$ $211.3\,kJ\,mol^{-1}$
$I_2(s) \rightarrow I_2(g),$ $62.76\,kJ\,mol^{-1}$

Given that the standard states for iodine and chlorine are $I_2(s)$ and $Cl_2(g),$ the standard enthalpy of formation for $ICl(g)$ is : ............... $\mathrm{kJ\,mol}^{-1}$

  • $+16.8$
  • B
    $+244.8$
  • C
    $-14.6$
  • D
    $-16.8$

Answer

Correct option: A.
$+16.8$
a
$\mathrm{I}_{2}(s)+C l_{2}(g) \rightarrow 2 \mathrm{ICl}(g)$

$\Delta A=\left[\Delta \mathrm{I}_{2}(s) \rightarrow I_{2}(g)+\Delta H_{\mathrm{I}-I}+\Delta H_{Cl-Cl} \right]-2\left[\Delta H_{\mathrm{I}-Cl}\right]$$=151.0+242.3+62.76-2 \times 211.3$

$=33.46$

$\Delta H_{f}^{o}(\mathrm{I} C l)=\frac{33.46}{2}$

$=16.73 \mathrm{\,kJ} / \mathrm{mol}$

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