$MVr = M ^0 L ^0 T ^0$

$M ^0 \frac{ L ^1}{ T ^1} \cdot L ^1= M ^0 L ^0 T ^0$

$L ^2= T ^1$   $. . . . . . .(1)$

Force $= M ^1 L ^1 T ^{-2} \quad \text { (in SI) }$

$= M ^0 L ^1 L ^{-4}$(In new system from equation $(1)) $

$= L ^{-3}$

Energy $= M ^1 L ^2 T ^{-2} \quad \text { (In SI) }$

$= M ^0 L ^2 L ^{-4}$ (In new system from equation $ (1)) $

$= L ^{-2}$

Power $=\frac{\text { Energy }}{\text { Time }}$

$= M ^1 L ^2 T ^{-5} \quad \text { (in SI) }$

$=M^0 L^2 L^{-6} $ (In new system from equation $(1)) $

$= L ^4$

Linear momentum $= M ^1 L ^1 T ^{-1} \text { (in SI) }$

$=M^0 L^1 L^{-2} $ (In new system from equation $(1)) $

$= L ^{-1}$

Ans. $(1,2,4)$