MCQ
light waves producing interference have their amplitudes in the ratio $3: 2$. The intensity ratio of maximum and minimum of interference fringes is
- A$36: 1$
- B$9: 4$
- ✓$25: 1$
- D$6: 4$
✓
Answer
Correct option: C.
$25: 1$
$\frac{I_{\max }}{I_{\min }}=\left(\frac{\frac{a_1}{a_2}+1}{\frac{a_1}{a_2}-1}\right)^2=\frac{25}{1}$
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