MCQ
$\lim _{x \rightarrow 0} \frac{\sin \left(x^2+5 x\right)}{x}=$
  • A
    6
  • B
    1
  • C
    -1
  • 5

Answer

Correct option: D.
5
(D)
$\lim _{x \rightarrow 0} \frac{\sin \left(x^2+5 x\right)}{x}=\lim _{x \rightarrow 0} \frac{\sin \left(x^2+5 x\right)}{x(x+5)} \times(x+5)$
$=1(0+5)$
$=5$

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