Question
$\lim _{x \rightarrow 2} \frac{x^2-3 x+2}{x^2+x-6}$

Answer


$\begin{array}{l}\lim _{x \rightarrow 2} \frac{x^2-3 x+2}{x^2+x-6}=\lim _{x \rightarrow 2} \frac{(x-2)(x-1)}{(x-2)(x+3)}=\lim _{x \rightarrow 2} \frac{(x-1)}{(x+3)} \\ =\frac{2-1}{2+3}=\frac{1}{5}\end{array}$

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