MCQ
$
\lim _{x \rightarrow 3}\left[\frac{5^{x-3}-4^{x-3}}{\sin (x-3)}\right]=
$
  • A
    $\log 5-4$
  • $\log \frac{5}{4}$
  • C
    $\frac{\log 5}{\log 4}$
  • D
    $\frac{\log 5}{4}$

Answer

Correct option: B.
$\log \frac{5}{4}$
(B) $\log \frac{5}{4}$
Hint:
$
\begin{aligned}
& \lim _{x \rightarrow 3} \frac{5^{x-3}-4^{x-3}}{\sin (x-3)} \\
& \text { put } x-3=h \\
\therefore \quad & x=3+h \\
& \text { As } x \rightarrow 3, h \rightarrow 0 \\
\therefore \quad & \text { Required limit } \\
& =\lim _{h \rightarrow 0} \frac{5^h-4^h}{\sinh }\\
& =\lim _{h \rightarrow 0} \frac{\left(5^h-1\right)-\left(4^h-1\right)}{\sin h} \\
& =\frac{\lim _{h \rightarrow 0} \frac{\left(5^h-1\right)}{h}-\frac{\left(4^h-1\right)}{h}}{\lim _{h \rightarrow 0} \frac{\sin h}{h}} \quad \cdots\left[\lim _{x \rightarrow 0} \frac{a^x-1}{x}=\log a\right] \\
& =\frac{\log 5-\log 4}{1} \\
= & \log \left(\frac{5}{4}\right)
\end{aligned}
$

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