MCQ
$\lim_{x \rightarrow 0}\ \ x^x= .....$
- A8
- B6
- ✓0
- D9
$\therefore log \ y = \lim_{x \rightarrow 0}x\ log\ x$
$\therefore \log y=\lim_{x \rightarrow 0}\frac{log \ x}{\left(\frac{1}{x}\right)}\ \left(\frac{\infty}{\infty}\right)$
$\therefore \log y=\lim_{x \rightarrow 0}\frac{\left(\frac{1}{x}\right)}{\left(\frac{-1}{x^2}\right)}$
$\therefore \log y=\lim_{x \rightarrow 0}(-x)$
$\therefore \log y=0$
$\therefore y=1$
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$ = \tan \alpha \tan \beta \tan \gamma $, તો $(\sec \alpha - \tan \alpha )(\sec \beta - \tan \beta )$$(\sec \gamma - \tan \gamma ) = $