MCQ
$\lim_{x \rightarrow 0}\frac{(2-3x)^{-5}-2^{-5}}{x} =$ ......
- A$\frac{3}{32}$
- B$\frac{-10}{64}$
- ✓$\frac{15}{64}$
- D$\frac{-32}{3}$
$\lim_{x \rightarrow 0} \frac{(2-3x)^{-5}-2^{-5}}{x}$
$\left(\frac{0}{0}\right) from$
$\lim_{x \rightarrow 0} \frac{-5(2-3x)^{-6}(-3)}{1} \, \, \, \, L^1Hospital.$
$=-5(2)^{-6} \times (-3)$
$=\frac{15}{2^6} $
$= \frac{15}{64}$
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$(1), (2, 3), (4, 5, 6), (7, 8, 9, 10) ,\,.\,.$ વગેરે. . . . તો $n$ માં વિભાગમાં આવેલી સંખ્યાોનો સરવાળો શોધો.