MCQ
$\lim_{x \rightarrow \infty} \frac{\int\limits_{0}^{2x}{x{{e}^{2}}dx}}{{{e}^{4{{x}^{2}}}}}=.......$
- A$0$
- B$\infty $
- C$2$
- ✓$\frac{1}{2}$
$\lim_{x \rightarrow \infty} \frac{\int_{0}^{2x} xe^2dx }{e^{4x^2}}$
$=\lim_{x \rightarrow \infty} \frac{\int_{0}^{2x}xe^{x^2}dx}{e^{4x^2}}$
$=\lim_{x \rightarrow \infty} \frac{\int_{0}^{2x}e^{x^2}dx}{2e^{4x^2}}$
$=\lim_{x \rightarrow \infty} \frac{[e^{x^2}]_{0}^{2x}}{2e^{4x^2}}$
$=\lim_{x \rightarrow \infty} \frac{[e^{x^2}]^{2x}_0}{2e^{4x^2}} \Rightarrow \lim_{x \rightarrow \infty} \frac{e^{4x^2}-1}{2e^{4x^2}}$
$=\lim_{x \rightarrow \infty} \left(\frac{1}{2}- \frac{1}{2e^{4x^2}}\right)$
$=\frac{1}{2}-\frac{1}{\infty}$
$=\frac{1}{2}-0$
$=\frac{1}{2}$
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