MCQ
limx→0 x sin $ \frac{1}{\text{x}}$ is equal to:
- A0
- B1
- C$ \frac{1}{2}$
- Ddoes not exist
Solution:
We know that,
$= \lim_\limits{\text{x}→0} \text{x} = 0$
And
$= -1 ≤ \sin \frac{1}{\text{x}} ≤ 1$
By Sandwich theorem,
$$ $=\lim_\limits{\text{x}→0} \text{x} \sin \frac{1}{\text{x}} =0$
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