MCQ
Lines represented by $9 x^2+y^2+6 x y-4=0$ are
  • A
    coincident.
  • parallel but not coincident.
  • C
    not parallel.
  • D
    perpendicular.

Answer

Correct option: B.
parallel but not coincident.
(B) Given equation of pair of lines is $9 x^2+y^2+6 x y-4=0$
$\therefore \quad a=9, b=1, h=3$
$h^2-a b=3^2-9(1)=0$
$\therefore \quad$ The lines are parallel
Now, $9 x^2+6 x y+y^2=4$
$\Rightarrow(3 x+y)^2=4 \Rightarrow 3 x+y= \pm 2$
Hence, the lines are parallel and not coincident.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free