MCQ
The value of $\lambda$ for which the straight line $\frac{x-\lambda}{3}=\frac{y-1}{2+\lambda}=\frac{z-3}{-1}$ may lie on the plane $x-2 y=0$ is
- A1
- B$0$
- ✓$-\frac{1}{2}$
- Dthere is no such $\lambda$
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