The vapour pressure of pure liquid $B , P _{ B }=$ ?
$P _{\text {Total }} = P _{ A }^{\prime} X _{ A }+ P _{ B }^{-} X _{ B }$
$45 =20\left(\frac{1}{2}\right)+ P _{ B }^{(}\left(\frac{1}{2}\right)$
$90 =20+ P _{ B }^{-} \quad \Rightarrow P _{ B }^{-}=70 \text { torr }$
For new solution, $P _{\text {Total }}=22.5= P _{ A }^0 X _{ A }+ P _{ B }^{ C } X _{ B }$
$22.5 =20 x +70(1- x )$
$x =0.95= X _{ A }$
$X _{ B } =1- x =0.05$
$\therefore \frac{ X _{ A }}{ X _{ B }}= \frac{0.95}{0.05}=19.00$
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$\mathrm{A}+\mathrm{B} \rightarrow \mathrm{M}+\mathrm{N} \text { in } \mathrm{kJ} \mathrm{mol}^{-1}$ is equal to ...... . (Integer answer)
$\Delta {U_{BC}} = - 5\,kJ\,mo{l^{ - 1}},{q_{AB}} = 2\,kJ\,mo{l^{ - 1}}$
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